यदि `abc=1`, तब सिद्ध कीजिए कि `(1)/(1+a+b^(-1))+(1)/(1+b+c^(-1))+(1)/(1+c+a^(-1))=1`

Explanation

माना बाया पक्ष
`=(1)/(1+a+b^(-1))+(1)/(1+b+c^(-1))+(1)/(1+c+a^(-1))=(1)/(1+a+(1)/(b))+(1)/(1+b+(1)/(c ))+(1)/(1+c+(1)/(a))`
`=(b)/(b+ab+1)+(1)/(1+b+ab)+(1)/(1+(1)/(ab)+(1)/(a))`( `:'abc=1implies(1)/(c )=ab`व `c=(1)/(ab)`)
`=(b)/(b+ab+1)+(1)/(1+b+ab)+(ab)/(ab+1+b)=(b+1+ab)/(b+ab+1)=1=` दाया पक्ष