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BALAJI PUBLICATION-बीजगणितीय सर्वसमिकाऐं-बहुविकल्पीय प्रश्न
- यदि x + (1)/(x) = 3, तब x^(6) + (1)/(x^(6))=
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- यदि x - y = 5 व xy = 12, तब x^(2) + y^(2)=
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- यदि x^(2) + (1)/(x^(2))=102, तब x - (1)/(x)=
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- यदि x + (1)/(x) = 4, तब x^(4) + (1)/(x^(4))=
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- यदि x^(3) + (1)/(x^(3))=110, तब x + (1)/(x)=
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- यदि x - (1)/(x) = (15)/(4), तब x + (1)/(x)=
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- यदि x + y + z = 9, xy + yz + zx = 23, तब x^(3) + y^(3) + z^(3) - 3xyz=
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- यदि (x)/(y) + (y)/(x) = 1, तब x^(3) + y^(3) =
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- यदि x - y = -8 व xy = -12, तब x^(3) - y^(3)=
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- यदि x + y + z = 9 व xy + yz + zx = 23, तब x^(2) + y^(2) + z^(2)=
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