एक `Delta ABC ` में , `30 A = 6B = 5C, /_A, /_B ` or `/_C ` निकालिए

Explanation

दिया है, `30A= 6B = 5C`
`(A)/(1) = (B)/(5) = (C )/(6)` ( 30 से विभाजित करने पर )
`/_A : /_B : /_C = 1:5:6`
`Delta ABC ` में, `/_A + /_B + /_C = 180^(@) implies x^(@) + 5x^(@) + 6x^(@) = 180^(@)`
`= 12 x^(@) = 180^(@) implies x= (180^(@))/( 12^(@)) = 15^(@)`
`/_ A = x^(@) = 15^(@) , /_B = 5x^(@) = 5( 15^(@)) = 75^(@) , /_C = 6x^(@) = 6(15^(@)) = 6(15^(@)) = 90^(@)`
अतः `/_A = 15^(@) , /_B = 75^(@) , /_C = 90^(@)`