A tangent is drawn to the curve `y=8/x^2` in XY-plane at the point `A(x_0, y_0)`, where `x_0=2` and the tangent cuts the X-axis at a point B. Then `bar(AB).bar(OB) =`

A tangent is drawn to the curve y=8x^(2) at a point A(x_(1),y_(1)), where x_(1)=2. The tangent cuts the x-axis at the point B .Then the scalar product of the vectors vec AB and vec OB is: 3 b.-3 c.6d.-6

The tangent drawn at the point (0, 1) on the curve y=e^(2x) meets the x-axis at the point -

The tangent to the curve x^2+y^2-2x-3=0 is parallel to X-axis at the points

The tangent drawn at the point (0,1) on the curve y = e^(2x) meets x-axis at the point

The tangent to the curve y=x^(2)+3x will pass through the point (0,-9) if it is drawn at the point

Find the equation of tangents to the curve y = (x^(3) - 1) (x - 2) at the points, where the curve cuts the X-axis.

The equation to the tangent to the curve y=be^(x//a) at the point where x=0 is

The slope of the tangent to the curve y=x^(2) -x at the point where the line y = 2 cuts the curve in the first quadrant, is

The slope of the tangent to the curve y=x^(2) -x at the point where the line y = 2 cuts the curve in the first quadrant, is