Divide `c^4-d^4`by c+d

Divide: x^4-y^4b y\ x^2-y^2 (ii) a c x^2+\ (b c+a d)x+b d\ b y\ (a x+b)

If a means 'plus', b means 'minus', c means 'multiplied by' and d means 'divided by then 18 c 14 a 6 b 16 d 4 = ?

If A and B are divided by D, then the remainder obtained are 13 and 31 respectively where A, B, C are natural numbers. Further A + B is divided by the same divisor D the remainder is 4, then the divisor D is :

If a number when divided by 4, is reduced by 21, the number is a. 18 b. 20 c. 28 d. 38

If "A" means "minus", "B" means "divided by", "C" means "plus" and ''D'' means "multiplied by", then 54 B 6 A 4 C 2 D 5 = ?

What is the remainder when 4^(96) is divided by 6? (a) 4 (b) 3 (c) 2 (d) 1

When n is divided by 4, the remainder is 3. What is the remainder when 2n is divided by 4? 1 (b) 2 (c) 3 (d) 6

The remainder when the number 3^(256) - 3^(12) is divided by 8 is (a) 0 (b) 3 (c) 4 (d) 7

What is the remainder when 2^(31) is divided by 5? 1 (b) 2 (c) 3 (d) 4