`(dy)/(dx)` ज्ञात कीजिए, यदि-
`x=a(theta+sintheta),y=a(1-costheta)`

Explanation

यहाँ `x=a(theta+sintheta),y=a(1-costheta)`
`therefore(dx)/(dtheta)=a(1+costheta),(dy)/(dtheta)=asintheta`
अब, `(dy)/(dx)=(dy//dtheta)/(dx//dtheta)=(asintheta)/(a(1+costheta))`
`rArr(dy)/(dx)=(2sintheta/2costheta/2)/((1+2cos^(2)theta/2-1))`
`rArr(dy)/(dx)=(2sintheta/2costheta/2)/(2cos^(2)theta/2)=(sintheta/2)/(costheta/2)=tantheta/2`