किसी अभिक्रिया के `500 k` तथा `700 k` ताप पर वेग स्थिरांक क्रमश: 0.02 `S^(-1)` तथा `0.07 S^(-1)` है तो `E_(a)` तथा A की गणना कीजिए।

Explanation

`log .(k_(2))/(k_(1)) = (E_(a))/(2.303R ) .((T_(2)-T_(1))/(T_(1)T_(2))]`
`k_(1) =0.02 s^(-1) k_(2) = 0.07 s^(-1) ,T_(1) = 500 k, T_(2) =700 k`
`R= 8.31 4 j k^(-1) mol^(-1)`
`log .(0.07)/(0.02) =((E_(a))/(2.303 xx 8.314jk^(-1) mol^(-1))) [(700- 500)/(500xx 700)]`
`0.5441 = (E_(a) xx 200)/(67014997)`
`E_(a) = (0.441 xx 67014997)/(200)`
`E_(a) =18232.2 j`
`k= Ae^(-Ea//RT)`
`T= 500 k` पर `k= 0.02 s^(-1)`
`log k = log A- (E_(a))/(2.303RT)`
`log A = log k + (E_(a))/(2.303 RT)`
`log A = log 0.02 + (18232.2))/(2.303 xx 8.314 xx 500)`
` logA = log (10^(-2) xx 2) + (18232.2)/(9573.57)`
`log A =-2 log .10 + log 2+ 1.9044`
`log A= - 2 + 0.3010 + 1.9044`
`log A= - 1.699 + 1.9044`
`log a = 0. 2054`
A = Anti log 0.2054`
`=1.604`