For `n in N, 1/5n^5+1/3n^3+7/15n` is

Using mathematical induction, prove that 1/5n^5+1/3n^3+7n/15 is a natural number where ninN .

For all n in N, 3n^(5) + 5n^(3) + 7n is divisible by

For all n in N, 3n^(5) + 5n^(3) + 7n is divisible by

For all n in N, (n^(5))/(5)+(n^(3))/(3)+(7)/(15n) is

For all n in N, (n^(5))/(5)+(n^(3))/(3)+(7n)/(15) is

Prove the following by the method of induction for all n in N : 1/1.3 + 1/3.5 + 1/5.7+...+ 1 / ((2n-1)(2n+1)) = n / (2n+1)

Prove by the method of Induction for all n in N : 1/3.5 + 1/5.7 + 1/7.9 + …. n terms = n/(3(2n+3))

Prove by Principle of Mathematical Induction, that (n^5/5 + n^3/3+ (7n)/15) is a natural number for all n in N.

If ninNN , then by princuple of mathematical induction prove that, (1)/(5)n^(5)+(1)/(3)n^(3)+(1)/(15)*7n is an integer.