`2^(x)+2^(y)=2^(x+y)`

If 2^(x) +2y =2^(x+y),then (dy)/(dx)=

The axis of a parabola is along the line y=x and the distance of its vertex and focus from the origin are sqrt(2) and 2sqrt(2), respectively.If vertex and focus both lie in the first quadrant, then the equation of the parabola is (x+y)^(2)=(x-y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=8(x+y-2)

Add : x^(2) y^(2) , 2x^(2)y^(2) , - 4x^(2)y^(2) , 6x^(2)y^(2)

If x ^(2) - 2x ^(2) y ^(2) + 5x + y-5 =0 and y (1) then y '' (1)=

The axis of a parabola is along the line y=x and the distance of its vertex and focus from the origin are sqrt(2) and 2sqrt(2) , respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is (x+y)^2=(x-y-2) (x-y)^2=(x+y-2) (x-y)^2=4(x+y-2) (x-y)^2=8(x+y-2)

If x^(2)+(x)/(y^(2))=y^(2)+(y)/(x^(2))=2 then find x^(2)+y^(2)

If x,y,z are in AP,then show that the following are also in AP: (y+z)^(2)-x^(2),(z+x)^(2)-y^(2),(x+y)^(2)-z^(2)

The radical centre of the circles x^(2) + y^(2) - x + 3y-3 = 0 , x^(2) + y^(2) - 2x + 2y + 2= 0 , x^(2) + y^(2) + 2x +3y - 9 = 0 is