If `vecr=alpha(vecbxxvecc)+beta(veccxxveca)+gamma(vecaxxvecb)` and `[veca vecb vecc]=2` then `alpha+beta+gamma`

If veca,vecb,vecc are mutually perpendicular vector and veca=alpha(vecaxxvecb)+beta(vecbxxvecc)+gamma(veccxxveca) and [veca vecb vecc]=1 , then alpha+beta+gamma= (A) |veca|^2 (B) -|veca|^2 (C) 0 (D) none of these

If veca,vecb,vecc are mutually perpendicular vector and veca=alpha(vecaxxvecb)+beta(vecbxxvecc)+gamma(veccxxveca) and [veca vecb vecc]=1 then vecalpha+vecbeta+vecgamma= (A) |veca|^2 (B) -|veca|^2 (C) 0 (D) none of these

If veca,vecb,vecc are mutually perpendicular vector and veca=alpha(vecaxxvecb)+beta(vecbxxvecc)+gamma(veccxxveca) and [veca vecb vecc]=1 then vecalpha+vecbeta+vecgamma= (A) |veca|^2 (B) -|veca|^2 (C) 0 (D) none of these

If veca,vecb,vecc are mutually perpendicular vector and veca=alpha(vecaxxvecb)+beta(vecbxxvecc)+gamma(veccxxveca) and [veca vecb vecc]=1 then vecalpha+vecbeta+vecgamma= (A) |veca|^2 (B) -|veca|^2 (C) 0 (D) none of these

If vec(alpha)=x(vecaxxvecb)+y(vecbxxvecc)+z(veccxxveca) and [veca vecb vecc]=1/8 , then x+y+z=

If vec(alpha)=x(vecaxxvecb)+y(vecbxxvecc)+z(veccxxveca) and [veca vecb vecc]=1/8 , then x+y+z=

If alpha(veca xx vecb)+beta(vecb xx vecc)+gamma(vecc xx veca)=0 , then

Prove that: [vecaxxvecb ,vecbxxvecc ,veccxxveca] = [veca vecb vecc]^2

If [vecaxxvecb vecbxxvecc veccxxveca]=lambda[veca vecb vecc]^2 , then lambda is equal to :

If [(vecaxxvecb, vecbxxvecc, veccxxveca)]=lamda[(veca, vecb, vecc)]^(2) , then lamda is equal to