The coordinates of the points A and B are respectively `(1, 0)` and `(-1, 0)` and there is a point `Q` such that `AQ - BQ = +- 1` satisfy this relation then the locus of point Q is:

A ( - 9, 0) ,B ( - 1, 0) are two points. If P is a point such that PA : PB = 3 : 1 , then the locus of P is

Let coordinates of the points A and B are (5, 0 ) and (0, 7) respectively. P and Q are the variable points lying on the x- and y-axis respectively so that PQ is always perpendicular to the line AB. Then locus of the point of intersection of BP and AQ is

Let coordinates of the points A and B are (5,0) and (0,7) respectively. P and Q the variable point lying on the x-axis and y-axis respectively so that PQ is always perpendicular to the line AB. The locus of the point of intersection BP and AQ is

Plot the points P(1,0),Q(4,0), and S(1,3). Find the coordinates of the point R such that PQRS is a square.

ABCD is a parallelogram. If the points A , B and C are respectively : (0,0), (2,2),(1,3) Find the coordinates of the point D.

If P is the point (1,0) and Q lies on the parabola y^(2)=36x , then the locus of the mid point of PQ is :

ABCD is a parallelogram. If the points A , B and C are respectively : (-2,-1), (3,0),(0,-2) Find the coordinates of the point D.

The coordinates of a point which divide the line joining the points P(2,3,1) and Q(5,0,4) in the ratio 1:2 are