The number of electrons that must be removed from an electrically neutral silver dollar to give it a charge of +2.4C is

Options

A. `2.5xx10^(19)`
B. `1.5xx10^(19)`
C. `1.5xx10^(-19)`
D. `2.5xx10^(-19)`

Explanation

To find the number of electrons that must be removed from an electrically neutral silver dollar to give it a charge of +2.4 C, we can use the relationship between charge, the number of electrons, and the charge of a single electron.

### Step-by-step Solution:

1. **Understand the relationship between charge and electrons**:
The charge \( q \) can be expressed in terms of the number of electrons \( n \) and the charge of a single electron \( e \):
\[ q = n \times e \]
where \( e = 1.6 \times 10^{-19} \) C (the charge of one electron).

2. **Rearrange the formula to find \( n \)**:
To find the number of electrons \( n \), we can rearrange the formula:
\[ n = \frac{q}{e} \]

3. **Substitute the given values**:
Substitute \( q = 2.4 \) C and \( e = 1.6 \times 10^{-19} \) C into the equation:
\[ n = \frac{2.4}{1.6 \times 10^{-19}} \]

4. **Perform the division**:
First, calculate \( \frac{2.4}{1.6} \):
\[ \frac{2.4}{1.6} = 1.5 \]
Now, include the power of ten:
\[ n = 1.5 \times 10^{19} \]

5. **Conclusion**:
Therefore, the number of electrons that must be removed from the silver dollar to give it a charge of +2.4 C is:
\[ n = 1.5 \times 10^{19} \]