If an object of mass 1 kg contains `4xx10^(20)` atoms. If one electron is removed from every atom of the solid, the charge gained by the solid in 1 g is

Options

A. 2.8 C
B. `6.4xx10^(-2) C`
C. `3.6xx10^(-3) C`
D. `9.2xx10^(-4) C`

Explanation

To solve the problem step by step, we need to find the charge gained by the solid when one electron is removed from each atom, specifically for 1 gram of the solid.

### Step 1: Determine the number of atoms in 1 gram of the solid.
Given that the mass of the object is 1 kg and it contains \(4 \times 10^{20}\) atoms, we can find the number of atoms in 1 gram.

\[ \text{Number of atoms in 1 kg} = 4 \times 10^{20} \text{ atoms} \]
\[ \text{Number of atoms in 1 g} = \frac{4 \times 10^{20} \text{ atoms}}{1000 \text{ g}} = 4 \times 10^{17} \text{ atoms} \]

### Step 2: Calculate the total charge gained by removing one electron from each atom in 1 gram.
The charge of one electron is approximately \(1.6 \times 10^{-19}\) coulombs. If one electron is removed from each atom, the total charge gained can be calculated as follows:

\[ \text{Total charge (Q)} = \text{Number of atoms} \times \text{Charge of one electron} \]
\[ Q = 4 \times 10^{17} \text{ atoms} \times 1.6 \times 10^{-19} \text{ C} \]

### Step 3: Perform the multiplication to find the total charge.
Now we calculate the total charge:

\[ Q = 4 \times 1.6 \times 10^{-2} \text{ C} = 6.4 \times 10^{-2} \text{ C} \]

### Final Answer:
The charge gained by the solid in 1 gram is \(6.4 \times 10^{-2}\) coulombs.

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