The acceleration for electron and proton due to electrical force of their mutual attraction when they are 1 Å apart is

Options

A. `3.1xx10^(22)ms^(-2),1.3xx10^(19)ms^(-2)`
B. `3.3xx10^(28)ms^(-2),3.2xx10^(16)ms^(-2)`
C. `2.5xx10^(22)ms^(-2),1.4xx10^(19)ms^(-2)`
D. `2.5xx10^(18)ms^(-2),1.3xx10^(16)ms^(-2)`

Answer

C

Explanation

Force of mutual attraction between an electron and a proton
`F=1/(4piepsilon_(0))e^(2)/r^(2)=(9xx10^(9)(1.6xx10^(-19))^(2))/((10^(-10))^(2))=2.3xx10^(-8)N`
Acceleration of electron `=F/m_(e)=(2.3xx10^(-8))/(9xx10^(-31))`
`=2.5xx10^(22)ms^(-2)`
Acceleration of proton `=F/m_(p)=(2.3xx10^(-8))/(1.6xx10^(-27))`
`=1.4xx10^(19)ms^(-2)`