An electric dipole is placed at an angle...

An electric dipole is placed at an angle of `30^(@)` with an electric field intensity `2xx10^(5)N//C`. It experiences a torque equal to `4Nm`. The charge on the dipole, if the dipole is length is `2 cm`, is

8 mC

4 mC

6 mC

2 mC

Text Solution

Verified by Experts

The correct Answer is:

Here, `E=2xx10^(5)NC^(-1),l=2cm,tau=4Nm`
Torque, `vectau=vecpxxvecE,tau=pEsintheta`
`therefore" "4=pxx2xx10^(5)xxsin30^(@)orp=4xx10^(-5)Cm`
`therefore" "` Charge, `q=p/l=(4xx10^(-5)Cm)/(0.02m)=2xx10^(-3)C=2 mC`

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