Home
Class 12
PHYSICS
Electric field intensity at a point B d...

Electric field intensity at a point B due to a point charge Q kept at point A is `24 NC^(-1)`, and electric potential at B due to the same charge is `12 JC^(-1)`. Calculate the distance `AB` and magnitude of charge.

A

`10^(-6)C`

B

`10^(-7)C`

C

`10^(-10)C`

D

`10^(-9)C`

Text Solution

Verified by Experts

The correct Answer is:
D
Electric field of a point charge.
`E=1/(4piepsilon_0) q/r^2=24 N C^(-1)`
Electric potential of a point charge,
`E=1/(4piepsilon_0) q/r=12 J C^(-1)`
The distance PQ is `r=V/E=12/24`=0.5 m
`therefore` Magnitude of charge
`q'=4piepsilon_0 Vr`
`=1/(9xx10^9)xx12xx0.5=0.667xx10^(-9)` C
`=10^(-9)` C
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    NCERT FINGERTIPS|Exercise Potential Due To An Electric Dipole|5 Videos

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    NCERT FINGERTIPS|Exercise Potential Due To A System Of Charges|7 Videos

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

  • ELECTROMAGNETIC WAVES

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

  • MAGNETISM AND MATTER

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

Electric field intensity at a point B due to a point charge Q kept at a point charge Q kept at point A is 24 NC^(-1) , and electric potential at B due to the same charge is 12 JC^(-1) . Calculate the distance AB and magnitude of charge.

Electric field intensity at point P due to charge distributed over a sphere is:

The electric field at a point due to a point charge is 20 NC^(-1) and electric potential at that point is 10 JC^(-1) . Calculate the distance of the point from the charge and the magnitude of the charge.

" Electric field intensity due to a point charge " "q" ' at a distance 'r' from it is "

The electric field at a point due to a point is 10NC^(-1) and the electric potential at that point is 15JC^(-1) Calculate the distance of the point from the charge and the magnitude of the charge.

Electric field due to point charge

Derive an expression for electric field intensity at a point due to point charge.

The electric field at a point due to a point a charge is 30 N//C , and the electric potential at that point is 15 J//C . Calcualte the distance of the point from the charge and the magnitude of the charge.

Electric field at origin due to a point charge 1 nC placed at (1 ,1) m in x-y plane is