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A copper plate of thickness b is placed ...

A copper plate of thickness b is placed inside a parallel plate capacitor of plate distance d and area A as shown in figure. The capacitance of capacitor is

A

`(epsi_(0)A)/(d+(b)/(2))`

B

`(epsi_(0)A)/(2d)`

C

`(epsi_(0)A)/(d-b)`

D

`(2 epsi_(0)A)/(d+(b)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
As capacitance `C_(o) = (epsi_(0)A)/(d)`
`therefore ` after inserting copper plate `C = (epsi_(0)A)/(d-b)`
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