A capacitor has some dielectric between its plates, and the capacitor is connected to a DC source. The battery is now disconnected and then the dielectric is removed. State whether the capacitance, the energy stored in it, electric field, charge stored and the voltage will increase ro remain constant.

Options

A. capacitance will increase.
B. energy stored will decrease.
C. electric field will increase.
D. voltage will decrease.

Answer

C

Explanation

When the capacitor is connected to dc source , it get charged . The battery is then disconncted , so no more charge can flow in . On removing dielectric capacitance decrease.
Energy stored `(u = (q^(2))/(2C))` will increase.
Potential `(V = (q)/(C))` will also increase.
Electric field `(E = (V)/(D))` will increase.