Two spherical conductors each of capacity `C` are charged to potetnial `V` and `-V`. These are then conneted by means of a fine wire. The loss of energy will be

Options

A. zero
B. `1/2CV^(2)`
C. `CV^(2)`
D. `2CV^(2)`

Answer

C

Explanation

Here, loss of energy
`= (C_(1)C_(2)(V_(1) +V_(2)))/(2(C_(1)+C_(2))) = (C C(V+V)^(2))/(2(C+C)) = CV^(2)`