What is the energy stored in the capacitor between terminals `a` and `b` of the network shown in the figure? (Capacitance of each capacitor `C=1muF`)

Options

A. `12.5 mu J`
B. Zero
C. `25muJ`
D. `52 muJ`

Answer

A

Explanation

Network is redraw as shown in figure . This is a balacned Wheatstone's newtork.
Equivalent capacitance `C_(eq) = C`
Charge on a capacitor
`=(1((Q)/(z))^(2))/(2C) = (Q)/(8C) = (C^(2)V^(2))/(8C) = (CV^(2))/(8)`
Given : `C = 1 muF , V = 10 V`
` = ((1 xx 10^(-6))xx 10^(2))/(8) = (100)/(8) xx 10^(-6) = 12.5 muJ`