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A strong magnetic field is applied on a ...

A strong magnetic field is applied on a stationary electron, then

A

moves in the direction of the field.

B

remained stationary.

C

moves perpendicular to the direction of the field.

D

moves opposite to the direction of the field.

Text Solution

Verified by Experts

The correct Answer is:
B

As `vecF=vecq(vecv xx vecB)`
As the electron is stationary, `therefore` velocity `vecv=0`
`therefore" "vecF=0`. So, electron will remain stationary.
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