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A 2.5 m long straight wire having mass o...

A 2.5 m long straight wire having mass of 500 g is suspended in mid air by a uniform horizontal magnetic field B. If a current of 4 A is passing through the wire then the magnitude of the field is `("Take g "10 m s^(-2))`

A

0.5T

B

0.6T

C

0.25T

D

0.8T

Text Solution

Verified by Experts

The correct Answer is:
A
Here, `m=500g = 0.5kg, I=4A, l=2.5m`
As `F=Il B sin 90^(@)," "(because theta=90^(@) and F=mg)`
`therefore" "B=(mg)/(Il)=(0.5xx10)/(4xx2.5)=0.5T`
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