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The horizontal component of earth's magn...

The horizontal component of earth's magnetic field at a certain place is `3.0 xx 10^(-5) T` and having a direction from the geographic south to geographic north. The force per unit length on a very long straight conductor carrying a 12 A in east to west direction is

A

`3.0xx10^(-5)Nm^(-1)`

B

`3.2xx10^(-5)Nm^(-1)`

C

`3.6xx10^(-5)Nm^(-1)`

D

`3.8xx10^(-5)Nm^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
Force per unit length `f=(F)/(l)=IB sin theta.`
When the current is flowing from east to west then `theta=90^(@)`, hence
`F=IB sin 90^(@)=1.2xx3xx10^(-5)xx1=3.6xx10^(-5)"N m"^(-1)`
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