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An 8 cm long wire carrying a current of ...

An 8 cm long wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. If the magnetic field inside the solenoid is 0.3 T, then magnetic force on the wire is

A

0.14N

B

0.24N

C

0.34N

D

0.44N

Text Solution

Verified by Experts

The correct Answer is:
B
`F=Il B sin theta`
Here, `theta=90^(@),I=10A,`
`l= 8cm = 8xx10^(-2)m, B=0.3T`
`therefore" "F=10xx8xx10^(-2)xx0.3xxsin 90^(@)=0.24N`
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