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The magnetic force per unit length on a ...

The magnetic force per unit length on a wire carrying a current of 10 A and making an angle of `45^@` with the direction of a uniform magnetic field of 0.20 T is

A

`2sqrt2Nm^(-1)`

B

`2/sqrt2Nm^(-1)`

C

`sqrt2/2Nm^(-1)`

D

`4sqrt2Nm^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`l=10A, theta=45^(@), B=0.2T`
`therefore" "F=Il sinB theta`
`therefore" "(F)/(k)=Ibsin 45^(@)=10xx0.2xx(1)/(sqrt2)=(2)/(sqrt2)"N m"^(-1)`
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