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Two particles X and Y with equal charges...

Two particles `X` and `Y` with equal charges, after being accelerated throuhg the same potential difference, enter a region of uniform magnetic field and describe circular paths of radii `R_(1)` and `R_(2)` respectively. The ratio of the mass of `X` to that of `Y` is

A

`R_(1) //R_(2)`

B

`(R_(1)//R_(2))^(2)`

C

`(R_(2)//R_(1))`

D

`(R_(2)//R_(2))^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`qV=(1)/(2)Mv^(2) or v=sqrt((2qV)/(M))`
`"And "Bqv=(Mv^(2))/(R) or Bq=(Mv)/(R)=(M)/(R)sqrt((2qV)/(M))=(sqrt(2qVM))/(R)" ...(Using (i))"`
`or M=(B^(2)q^(2)R^(2))/(2qV)=(B^(2)qR^(2))/(2V)`
`therefore" "M prop r^(2)" "({:(because "B, q and V are same for the "),("given two particles"):})`
`"Hence "(M_(1))/(M_(2))=((R_(1))/(R_(2)))^(2)`
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