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The magnitude of the magnetic field at t...

The magnitude of the magnetic field at the centre of the tightly wound 150 turn coil of radius 12 cm carrying a current of 2 A is

A

18G

B

19.7G

C

15.7G

D

17.7G

Text Solution

Verified by Experts

The correct Answer is:
C
Here, `N=150, R = 12 cm = 12xx10^(-2)m, I=2A`
`therefore" "B=(mu_(0)NI)/(2R)=(2pixx10^(-7)xx150xx2)/(12xx10^(-2))=1.57xx10^(-3)T`
`=1.57xx10^(-3)T=15.7xx10^(-4)T=15.7G`
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