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A tightly wound 90 turn coil of radius 1...

A tightly wound 90 turn coil of radius 15 cm has a magnetic field of `4 xx 10^(-4)T` at its centre. The current flowing through it is

A

1.06A

B

2.44A

C

3.44A

D

4.44A

Text Solution

Verified by Experts

The correct Answer is:
A
Here, N = 90
R = 15 cm `=15xx10^(-2), B=4xx10^(-4)T`
`because" "B=(mu_(0)NI)/(2R)`
`therefore" "I=(2RB)/(Nmu_(0))=(2xx15xx10^(-2)xx4xx10^(-4))/(4pixx10^(-7)xx90)=1.06A.`
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