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A uniform conducting wire of length leng...

A uniform conducting wire of length length 10a and resistance R is wound up into four turn as a current carrying coil in the shape of equilateral triangle of side a. If current I is flowing 4 through the coil then the magnetic moment of the coil is

A

`(sqrt3)/(2)a^(2)I`

B

`(a^(2)I)/sqrt3`

C

`sqrt3a^(2)I`

D

`(2a^(2)I)/(sqrt3)`

Text Solution

Verified by Experts

The correct Answer is:
C
Magnetic moment M = NIA
`=4xxIxxa^(2)(sqrt3)/(4)=sqrt3a^(2)I`
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