The range of voltmeter of resistance `300 Omega` is 5 V. The resistance to be connected to convert it into an ammeter of range 5 A is

Options

A. ` 1 Omega "in series"`
B. `1 Omega "in parallel"`
C. `0.1 Omega "in series"`
D. `0.1 Omega "in parallel"`

Answer

B

Explanation

A voltmeter is a galvanometer having a high resistance connected in series with it. The current through the galvanometer is
`I_(g) = (5V)/(300 Omega) = 1/60 A`
An ammeter is a galvanometer having a low resistance connected in parallel with it. The shunt resistance S is determined from
`I_(g)/(I-I_(g)) = S/G`
where `G=3000 Omega` (Given)
For `I=5A`, we get
`(1//60)/(5-(1//60)) = S/300 rArr S= 1Omega`