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A current I=10A flows in a ring of radiu...

A current I=10A flows in a ring of radius `r_0=15 cm` made of a very thin wire. The tensile strength of the wire is equal to T=1.5N. The ring is placed in a magnetic field, which is perpendicular to the plane of th ering so that the forces tend to break the ring. Find B ( in T) at which the ring is broken.

A

0.5 T

B

1 T

C

2 T

D

2.5 T

Text Solution

Verified by Experts

The correct Answer is:
B

For the equilibrium of a small part of semicircular arc subtending an angle of `dtheta` at the center,
or `2T sin(d theta)/2 = (Bir_(0)d theta)/((10)(0.15)) = 1T`
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