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If the self inductance of 500 turns coil...

If the self inductance of 500 turns coil is 125 mH, then the self inductance of the similar coil of 800 turns is

A

`48.8 mH`

B

`200 mH`

C

`290 mH`

D

`320 mH`

Text Solution

Verified by Experts

The correct Answer is:
D
As `(L_(1))/(L_(2))=(N_(1)^(2))/(N_(2)^(2))`
Here seolrf inductance of 500 turns coil=125mH
`:.` L for coil of 800 turns `=(125)/((500)^(2))xx(800)^(2)=320 mH`
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NCERT FINGERTIPS-ELECTROMAGNETIC INDUCTION-Inductance
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