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A condenser of capacity C is charged to ...

A condenser of capacity `C` is charged to a potential difference of `V_(1)`. The plates of the condenser are then connected to an ideal inductor of inductance `L`. The current through the inductor wehnn the potential difference across the condenser reduces to `V_(2)` is

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The correct Answer is:
d
In case of ocillatory discharge of a apacitor through an inductor, charge at instant t is given by
`q=q_(0)cos omegat`
where `omega=(1)/(sqrt(LC))" "....(i)`
`:. cos omegat=(q)q_(0))=(CV_(2))/(CV_(1))=(V_(2))/(V_(1))" " ( :. Q=CV)`
Current through the inductor
`I=(dq)/(dt)=(d)/(qt)(q_(0)cos omegat)=-q_(0)omega sin omegat`
`|I|=CV_(1)(1)/(sqrt(LC))[1-cos^(2)omega]^(1//2)`
`=V_(1)sqrt((C)/(L))[-((V_(2))/(V_(1)))^(2)]^(1//2)=[(C(V_(1)^(2)-V_(2)^(2)))/(L)]" "` (Using (i))
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