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Let mp be the mass of a proton , mn the ...

Let `m_p` be the mass of a proton , `m_n` the mass of a neutron, `M_1` the mass of a `._10^20Ne` nucleus and `M_2` the mass of a `._20^40Ca` nucleus . Then

A

`M_2 = M_1`

B

`M_2 gt M_1`

C

`M_2 lt M_1`

D

`M_1 lt 10 (m_n + m_p)`

Text Solution

Verified by Experts

The correct Answer is:
D
Due to mass defect, the rest mass of a nucleus is always less than sum of the rest masses of its constituent nucleons.
`._10^20Ne` nucleus consists of 10 protons and 10 neutrons .
`therefore M_1 lt 10 (m_p + m_n)`
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