Radon has 3.8 days as its half-life . How much radon will be left out of 15 mg mass after 38 days ?

Options

A. 1.05 mg
B. 0.015 mg
C. 0.231 mg
D. 0.50 mg

Answer

B

Explanation

Here, `n=1/T_(1//2)=38/3.8=10`
`N=N_0(1/2)^n=m=m_0(1/2)^n =15 mg xx (1/2)^10`
`=15/1024`=0.015 mg