Two particls are projected in air with speed u at angles `theta_(1) and theta_(2)` (both acute) to the horizontal, respectively. If the height reached by the first particle is greater than that of the second, then which one of the following is correct? where `T_(1) and T_(2)` are the time of flight.

Options

A. `theta_(1) gt theta_(2)`
B. `theta_(1) = theta_(2)`
C. `T_(1) lt T_(2)`
D. `T_(1) = T_(2)`

Answer

A

Explanation

Height, `H = (u^(2) sin^(2) theta)/(2g)`
For the same speed, `H prop sin^(2)theta`
`because H_(1) gt H_(2)` (Given) `therefore sin^(2) theta_(1) gt sintheta_(2) rArr T_(1) gt T_(2)`