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A particle is moving on a circular path ...

A particle is moving on a circular path of radius r with uniform speed v. What is the displacement of the particle after it has described an angle of `60^(@)`?

A

`rsqrt(2)`

B

`rsqrt(3)`

C

r

D

2r

Text Solution

Verified by Experts

The correct Answer is:
C
According to consine formula
`cos60^(@)=(r^(2)+r^(2)-x^(2))/(2r^(2))`
`2r^(2)cos60^(@)=2r^(2)-x^(2)`
`x^(2)=2r^(2)=2r^(2)cos60^(@)=2r^(2)[2sin^(2)30^(@)]=r^(2)`
`:.x=r`
Displacement AB =x=r
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