Home
Class 11
PHYSICS
A particle is moving on a circular path...

A particle is moving on a circular path with a constant speed 'v'. Its change of velocity as it moves from A to B is:

A

`2v sin (2theta)`

B

zero

C

`2v sin ((theta)/(2))`

D

`2 v cos ((theta)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`|vec(v)|=|vec(v)|=v`
`Deltavec(v)=vec(v)-vec(v)`
`:.|Deltavec(v)|=sqrt(v^(2)+v^(2)-2v^(2)costheta)`
`=sqrt(2v^(2)(1-costheta))=2vsin""(theta)/(2)`
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    NCERT FINGERTIPS|Exercise Miscellaneous Questions|14 Videos

  • MOTION IN A PLANE

    NCERT FINGERTIPS|Exercise Higher Order Thinking Skills|8 Videos

  • MOTION IN A PLANE

    NCERT FINGERTIPS|Exercise Projectile Motion|29 Videos

  • MECHANICAL PROPERTIES OF SOLIDS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

  • MOTION IN A STRAIGHT LINE

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

A body is moving in a circular path with a constant speed. It has .

A particle moves in a circular path with constant speed . Its motion is

If a particle is moving along a circular path with constant speed, then Its motion is

A particle is moving on a circular path with constant speed, then its acceleration will be

A particle is moving in a circle with a constant speed. Its moving is

A particle is moving on a circular path with constant speed v then the change in its velocity after it has desceibed an angle of 60^(@) will be

A particle is moving on a circular path with constant speed v. The magnitude of the change in its velocity after it has described an angle of 90^(@) is :

A particle is moving in a circle or radius r centred at O with constant speed v. The change in velocity in moving from P to Q (angle POQ=40^(@)) is :

A particle is moving along a circular path with a constant speed 30m//s . What is change in velociyt of a particle, when it describe and angle of 90^(@) at the centre of the circle

A particle is moving in a circle of radius r centred at O with constant speed v . What is the change in velocity in moving from A "to" B (/_ AOB = 40^@) ?