sin(alpha+beta)=(2ab)/(a^(2)+b^(2))

If alpha and beta be two roots of the equation a cos theta+ b sin theta=c , show that sin alpha+ sin beta=(2bc)/(a^(2)+b^(2)) ,sin alpha sin beta =(c^(2)-a^(2))/(a^(2)+b^(2)) and tan (alpha+ beta)=(2ab)/(a^(2)-b^(2))

If angles alpha and beta satisfy the equation a cos theta+ b sin theta= c(a,b,c are constants), prove that- (a) sin (alpha+ beta)= (2ab)/(a^(2)+b^(2)) (b) cos (alpha+beta)=(a^(2)-b^(2))/(a^(2)+b^(2)) (c) cos (alpha- beta)=(2c^(2)-(a^(2)+b^(2)))/(a^(2)+b^(2))

If alpha and beta are the two different roots of equations alpha cos theta+b sin theta=c , prove that (a) tan (alpha-beta)=(2ab)/(a^(2)-b^(2)) (b) cos(alpha+beta)=(a^(2)-b^(2))/(a^(2)+b^(2))

If alpha and beta are the two different roots of equations alpha cos theta+b sin theta=c , prove that (a) tan (alpha-beta)=(2ab)/(a^(2)-b^(2)) (b) cos(alpha+beta)=(a^(2)-b^(2))/(a^(2)+b^(2))

If sin alpha+sin beta=a\ a n d\ cosalpha+cosbeta=b , show that : sin(alpha+beta)=(2"a b")/(a^2+b^2)

If sin alpha+sin beta=a and cos alpha+cos beta=b show that sin(alpha+beta)=(2ab)/(alpha^(2)+beta^(2))

If alpha and beta are the solutions roots of a cos theta+b sin theta=c, then choose the correct option (A)sin alpha+sin beta=(2bc)/(a^(2)+b^(2))(B)sin alpha sin beta=(c^(2)-a^(2))/(a^(2)+b^(2))(C)sin alpha+sin beta=(a^(2)-b^(2))/(c^(2)+b^(2))(D)sin alpha sin beta=(a^(2)-b^(2))/(c^(2)+b^(2))(D)

If cos (theta - alpha) = a and sin(theta - beta) = b (0 lt theta - alpha, theta - beta lt pi//2) , then prove that cos^(2) (alpha - beta) + 2ab sin (alpha - beta) = a^(2) + b^(2)

If cos (theta - alpha) = a and sin(theta - beta) = b (0 lt theta - alpha, theta - beta lt pi//2) , then prove that cos^(2) (alpha - beta) + 2ab sin (alpha - beta) = a^(2) + b^(2)

If cos (theta - alpha) = a and sin(theta - beta) = b (0 lt theta - alpha, theta - beta lt pi//2) , then prove that cos^(2) (alpha - beta) + 2ab sin (alpha - beta) = a^(2) + b^(2)