`lim_(x->5) {x^lambda-5^lambda}/{x-5}`

lim_(x rarr oo)((x+lambda)/(x-lambda))^(x)=4 then lambda

The equation lambda^(2)x^(2)+(lambda^(2)-5 lambda+4)xy+(3lambda-2)y^(2)-8x+12y-4=0 will represent a circle, if lambda=

The equation lambda^(2)x^(2)+(lambda^(2)-5 lambda+4)xy+(3lambda-2)y^(2)-8x+12y-4=0 will represent a circle, if lambda=

If the equation (lambda^(2)-5 lambda+6)x^(2)+(lambda^(2)-3 lambda+2)x+(lambda^(2)-4)=0 is satisfied by more then two values of x then lambda=

the values of lambda for which (lambda^(2)-3 lambda+2)x^(2)+(lambda^(2)-5 lambda+6)+lambda^(2)-4=0 is identity in x is

Find the value of lambda if the equation x^2/(2-lambda)+y^2/(lambda-5)+1=0 represents an ellipse.

If f(x)=sum_(lambda=1)^(n)(x-(5)/(lambda))(x-(4)/(lambda+1)) then lim_(n rarr oo)f(0) is equal to

If f(x)=sum_(lambda=1)^(n)(x-(5)/(lambda))(x-(4)/(lambda+1)) then lim_(n rarr oo)f(0) is equal to