Home
Class 12
CHEMISTRY
If the distance between Na^(+) and Cl^(-...

If the distance between `Na^(+)` and `Cl^(-)` ions in NaCl crystals is 265 pm, then edge length of the unit cell will be ?

A

265 pm

B

795 pm

C

132.5 pm

D

530 pm

Text Solution

Verified by Experts

The correct Answer is:
D

In NaCl crystal , Edge length = 2 x distance between `Na^+` and `Cl^-`
=2 x 265 = 530 pm
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    NCERT FINGERTIPS|Exercise Calculations Involving Unit Cell Dimensions|9 Videos
  • THE SOLID STATE

    NCERT FINGERTIPS|Exercise Imperfections In Solids|18 Videos
  • THE SOLID STATE

    NCERT FINGERTIPS|Exercise Number Of Atoms In Unit Cell And Close Packed Structures|29 Videos
  • THE P-BLOCK ELEMENTS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

If the distance between Na^+ and Cl^(-) ions in NaCl crystal is 'a' pm, the edge length of the unit cell is

The distance between Na^(+) and CI^(-) ion ion NaCI is 281 pm. What is the edge length of the cube

If the distance between Na^+ and Cl^- ions of sodium chloride crystal is 'x' pm, then length of the edge of the unit cell is

In the distance between Na^(+) and CI^(-) ions in sodium chliride crystal is X pm , the length of the edge of the unit cell is

Assertion. The sum of the radii of Na^(+) and Cl^(-) ions in NaCl cystal is 281 pm Hence, edge of the unit cell is 281 pm. Reason. Edge of the unit cell is the distance between the centres of Na^(+) and Cl^(-) ions touching each other.

What is the distance between Na^(+) and Cl^(-) ions in NaCl crystal if density is 2.165"g cm"^(-3) ? NaCl crystallises in fcc lattice.