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Henry's law constant for the molality of...

Henry's law constant for the molality of methane in benzene at `298K `is `4.27xx10^(5)mm Hg`. Calculate the solubility of methane in benzene at `298 K` under `760 mm Hg`.

A

`1.78xx10^(-3)`

B

17.43

C

0.114

D

2.814

Text Solution

Verified by Experts

The correct Answer is:
A
According to Henry's law , `p=K_H x`
`x=p/K_H=760/(4.27xx10^5)=1.78xx10^(-3)`
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