Home
Class 12
CHEMISTRY
Henry's law constant of oxygen is 1.4 xx...

Henry's law constant of oxygen is `1.4 xx 10^(-3)` mol `"lit"^(-1) "atm"^(-1)` at 298 K. How much of oxygen is dissolved in 100 mL at 298 K when the partial pressure of oxygen is 0.5 atm?

A

22.4 mg

B

22.4 g

C

2.24 g

D

2.24 mg

Text Solution

Verified by Experts

The correct Answer is:
D
According to Henry's law , `s=K_Hxxp`, where s is concentration of `O_2` dissolved
`s=1.4xx10^(-3)xx0.5=0.7xx10^(-3)` mol/L
`s=n/V` or `n=0.7xx10^(-3)xx0.1=0.7xx10^(-4)` mol
`n=w/M` or w = n x M
`=0.7xx10^(-4) xx32=22.4xx10^(-4) ` g or 2.24 mg
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    NCERT FINGERTIPS|Exercise Vapour Pressure Of Liquid Solutions|5 Videos

  • SOLUTIONS

    NCERT FINGERTIPS|Exercise MCQs|2 Videos

  • SOLUTIONS

    NCERT FINGERTIPS|Exercise Expressing Concentration Of Solutions|16 Videos

  • PRACTICE PAPER -3

    NCERT FINGERTIPS|Exercise Practice Paper 3|50 Videos

  • SURFACE CHEMISTRY

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

The standard enthalpy of diamond is zero at 298K and 1 atm pressure.

Henry's law constant for the solubility of nitrogen gas in water at 298 K is 1.0 xx 10^(-5) atm . The mole fraction of nitrogen in air is 0.8 .The number of moles of nitrogen from air dissolved in 10 mol of water at 298 K and 5 atm pressure is

Henry law constant for oxygen dissolved in water is 4.34 xx 10^(4) atm at 25^(@) C . If the partial pressure of oxygen in air is 0.4 atm.Calculate the concentration ( in moles per litre) of the dissolved oxygen in equilbrium with air at 25^@C .

The lowest concentration of oxygen that can support aquatic life is about 1.3xx10^(-4)mol//L . The partial pressure of oxygen is 0.21 atm at sea level. What is the lowest partial pressure of oxygen that can support life ? k_(H)(O_(2))=11.3xx10^(-3)mol//L.atm

Which gas is most dense at 1 atm and 298 K ?