Home
Class 12
CHEMISTRY
What will be the degree of dissociation ...

What will be the degree of dissociation of 0.1 M `Mg(NO_3)_2` solution if van't Hoff factor is 2.74 ?

A

`75%`

B

`87%`

C

`100%`

D

`92%`

Text Solution

Verified by Experts

The correct Answer is:
B

`Mg(NO_3)_2 to Mg^(2+) + 2NO_3^-`
`alpha=(i-1)/(n-1)=(2.74-1)/(3-1)=1.74/2=0.87`
Degree of dissociation = 0.87 x 100 = 87%
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    NCERT FINGERTIPS|Exercise Higher Order Thinking Skills|10 Videos
  • SOLUTIONS

    NCERT FINGERTIPS|Exercise NCERT Exemplar|26 Videos
  • SOLUTIONS

    NCERT FINGERTIPS|Exercise Colligative Properties And Determination Of Molar Mass|32 Videos
  • PRACTICE PAPER -3

    NCERT FINGERTIPS|Exercise Practice Paper 3|50 Videos
  • SURFACE CHEMISTRY

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

What is the degree of dissociation for Ca(NO_(3))_(2) solution if van't Hoff factor = 2.4 ?

What is Van't Hoff factor ?

If alpha is the degree of dissociation of Na_(2)SO_(4) the van't Hoff's factor (i) used for calculating the molecular mass is

The degree of dissociation for K_(4)[Fe(CN)_(6)] is 60% . Calculate the Van't Hoff factor.

If alpha is the degree of dissociation of Na_(2)SO_(4) , the van,t Hoff factor (i) used for calculating molaecular mass is:

The degree of dissociation for PtCl_(4) complex is 70% . Calculate the Van't Hoff factor.