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What amount of CaCl2 (i=2.47) is dissolv...

What amount of `CaCl_2` (i=2.47) is dissolved in 2 litres of water so that its osmotic pressure is 0.5 atm at `27^@` C ?

A

3.42 g

B

9.24 g

C

2.834 g

D

1.820 g

Text Solution

Verified by Experts

The correct Answer is:
D
`pi=iCRT = I n/V RT`
`n=(pixxV)/(ixxRxxT) =(0.5xx2)/(2.47xx0.0821xx300)`=0.0164 mol
Amount of `CaCl_2=n xx M =0.0164 xx 111` = 1.820 g
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