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The van't Hoff factor of a 0.005 M aqueo...

The van't Hoff factor of a 0.005 M aqueous solution of KCl is 1.95. The degree of ionisation of KCl is :

A

0.95

B

0.97

C

0.94

D

0.96

Text Solution

Verified by Experts

The correct Answer is:
A
`KCl hArr K^(+) + Cl^(-) ` (n=2)
`alpha=(i-1)/(n-1)=(1.95-1)/(2-1)=0.95`
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