Home
Class 12
CHEMISTRY
The elevation in boiling point of a solu...

The elevation in boiling point of a solution of 9.43 g of `MgCl_2` in 1 kg of water is ( `K_b` = 0.52 K kg `mol^(-1)` , Molar mass of `MgCl_2 = 94.3 g mol^(-1)`)

A

0.156

B

0.52

C

0.17

D

0.94

Text Solution

Verified by Experts

The correct Answer is:
A
`MgCl_2 hArr Mg^(2+) + 2Cl^(-) , i=3`
`DeltaT_b=iK_bm=3xx0.52xx9.43/(94.3xx1)`=0.156
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    NCERT FINGERTIPS|Exercise Higher Order Thinking Skills|10 Videos

  • SOLUTIONS

    NCERT FINGERTIPS|Exercise NCERT Exemplar|26 Videos

  • SOLUTIONS

    NCERT FINGERTIPS|Exercise Colligative Properties And Determination Of Molar Mass|32 Videos

  • PRACTICE PAPER -3

    NCERT FINGERTIPS|Exercise Practice Paper 3|50 Videos

  • SURFACE CHEMISTRY

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

Calculate the boiling point of a solution prepared by adding 15.00 g of NaCl to 250 g of water . (K_(b) = 0.512 K kg mol^(-1) and molar mass of NaCl = 58.44 g mol^(-1) )

Calculate elevation in boiling point for 2 molal aqueous solution of glucose. (Given K_b(H_(2)O) = 0.5 kg mol^(-1) )

The elevation in boiling point of a solution of 13.44 g of CuCl_(2) (molecular weight = 134.4,k_(b)=0.52K "molality"^(-1)) in 1 kg water using the following information will be: