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4 L of 0.02 M aqueous solution of NaCl w...

4 L of 0.02 M aqueous solution of NaCl was diluted by adding 1 L of water. The molality of the resultant solution is……..

A

0.004

B

0.008

C

0.012

D

0.016

Text Solution

Verified by Experts

The correct Answer is:
D
`M_1V_1=M_2V_2`
0.02 M x 4 L = `M_2 ` x 5 L
`M_2=(0.02xx4)/5`=0.016 M
Here, molality will be equal to molarity as for NaCl, molecular weight is equal to its equivalent weight.
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