At 25^@C, Nernst equation is...

At `25^@C`, Nernst equation is

A

`E_"cell"=E_"cell"^@-"0.0591"/n "log" "[ion]"_"RHS"/"[ion]"_"LHS"`

B

`E_"cell"=E_"cell"^@-"0.0591"/n "log" "[M]"_"RHS"/"[M]"_"LHS"`

C

`E_"cell"=E_"cell"^@+"0.0591"/n "log" "[ion]"_"RHS"/"[ion]"_"LHS"`

D

`E_"cell"=E_"cell"^@-"0.0591"/n "log" "[ion]"_"LHS"/"[ion]"_"RHS"`

Text Solution

Verified by Experts

The correct Answer is:

A

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