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The standard reduction potential for Cu^...

The standard reduction potential for `Cu^(2+)//Cu` is `+0.34V`. Calculate the reduction potential at pH=14 for the above couple. `K_(SP)` of `Cu(OH)_(2)` is `1.0xx10^(-19)`

A

2.2 V

B

3.4 V

C

`-0.22` V

D

`-2.2` V

Text Solution

Verified by Experts

The correct Answer is:
C
`pH=-log[H^+]=14 rArr [H^+]=10^(-14)`
Hence, `[OH^-]=1M [H^+][OH^-]=10^(-4)`
`Cu(OH)_2 to Cu^(2+) + 2OH^-`
`K_"sp"=[Cu^(2+)][OH^-]^2`
For the reaction, `Cu^(2+) + 2e^(-) to Cu , n=2`
`E_"cell"=E_"cell"^@-0.0591/n"log"1/([Cu^(2+)])`
`E_"cell"=0.34-0.0591/2"log"1/(1xx10^(-19))`=-0.22 V
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